Nat ACL Query? – Community Engineering Stack Change

I’m so confused with fundamentals that I was an knowledgeable in,
so I’ve this topology

Please reply to my questions individually,

Query 1) So if I’ve two DNS severs, and ofc two IP tackle(81.1.1.30 & 31) obtainable from the ISP

This config can be suffice for Port forwarding?

Switch3650(config)#ip nat inside supply static 192.168.1.50 80 81.1.1.30 80

Switch3650(config)#ip nat inside supply static 192.168.1.51 80 81.1.1.31 80

Switch3650(config)#int vlan 1

Switch3650(config-if)#ip nat inside

Switch3650(config)#int fa1/2

Switch3650(config-if)#ip nat outdoors

and configuration of my outdoors interface solely has to have one IP tackle configured or two?

Switch3650(config)#int fa1/2

Switch3650(config-if)#ip add 81.1.1.30 255.255.255.254

**or** defining two ip addresses on my interface

Switch3650(config)#int fa1/2

Switch3650(config-if)#ip add 81.1.1.30 255.255.255.255

Switch3650(config-if)#ip add 81.1.1.31 255.255.255.255 secondary

am I attaining the identical outcome right here?
so when will we use secondary ip, once we cannot cowl our obtainable legitimate(public) IPs with subnet masks in a single line?

so what’s going to occur if I solely put one ip tackle on the skin interface? the nat will not translate anymore, as a result of it may well’t discover the skin interface, as a result of it is not listed within the routing desk, proper?

Switch3650(config-if)#ip add 81.1.1.30 255.255.255.255

Query 2)

so for instance I wanna PAT overload the remainder of my community which they aren’t these two servers and they’re shoppers with ip ranges from 192.168.1.1 to 192.168.1.49
how ought to I calculate the wild card masks?

Switch3650(config)#access-list 1 allow 192.168.1????????????

Switch3650(config)#ip nat inside supply record 1  81.1.1.30 80 overload

that is what I put

**0 0** 0 0 0 0 0 1 = 1

**0 0** 1 1 0 0 0 1 = 49

in line with this algorithm

Community Tackle is 0 which is fallacious it must be 1, as a result of it begins from 1,

what am I lacking?

the Netmask must be I assume: 192 equal to wildcard of 63

Please please reply to all my questions, I’m so confused

Thanks